In the previous quiestion the minimum force F required so that block A will slip on block B is:

Minimum force F required to move the block

Minimum force F required to move the block

A block of mass 2 kg is kept on a rough horizontal floor an pulled with a force F. If the coefficient of friction is 0.5. then the minimum force required to move the block is :-

A block of mass 2 kg is kept on a rough horizontal floor an pulled with a force F. If the coefficient of friction is 0.5. then the minimum force required to move the block is :-

A block of mass 2 kg is kept on a rough horizontal floor an pulled with a force F. If the coefficient of friction is 0.5. then the minimum force required to move the block is :-

In the arrangement shown in figure, m_A = m_B = 2kg. String is massless and pulley is frictionless. Block B is resting on a smooth horizontal surface, while friction coefficient beteen block A and B is mu=0.5 . the Maximum horizontal force F that can be applied so that block A does not slip over block B is.

Maximum amplitude of SHM so block A will not slip on block B, K=100N/m

A cubical block of side L rests on a rough horizontal surface with coefficient of friction mu . A horizontal force F is applied on the block as shown. If the coefficient of frictions sufficienty high so that the block does not slide before toppling, the minimum force required to topple the block is : .

In the previous problem. The friction force applied by ground on block B is

In the previous problem. The friction force applied by ground on block B is