The p.m.f. of a r.v. X is as follows :
`P(X=0)=3k^(3),P(X=1)=4k-10k^(2),P(X=2)=5k-1`,
`P(X=x)=0" for any other values of x, then k ="`

The p.m.f. of a r.v. X is as follows : P(X=0)=3k^(3),P(X=1)=4k-10k^(2),P(X=2)=5k-1 , P(X=x)=0" for any other values of x, then "P(0ltXlt3) =

The p.m.f. of a r.v. X is as follows : P(X=0)=3k^(3),P(X=1)=4k-10k^(2),P(X=2)=5k-1 , P(X=x)=0" for any other values of x, then "P(Xlt1) =

The p.m.f. of a.r.v. X is as follows: P( X=0) = 3k^ (3), P(X=1) = 4k-10k^ (2) , P(X=2)=5k-1, P(X=x)=0 for any other value of x, then value of k is

The p.m.f. of a.r.v. X is as follows: P( X=0) = 3k^ (3), P(X=1) = 4k-10k^ (2) , P(X=2)=5k-1, P(X=x)=0 for any other value of x, then value of k is

The pmf of r.v.X as follows. P(X=0)=3k^3,P(X=1)=4k-10k^2,P(X=2)=5k-1,P(X=x)=0 for any other value of x.(ii)Obtain the cdf F(x).

A random variable x has its range {0,1,2} and the probabilities are given by P(x=0) =3k^(3), P(x=1) =4k-10k^(2) , P(x=2) =5k-1 where k is a constant then k=

A random variable x had its range {0, 1, 2} and the probabilities are given by P(x=0)=3k^(3), P(x=1)=4k-10k^(2), P(x=2)=5k-1 where k is constant then k =

The probability distribution of random variable X is given as follows : {:(X = x_(i),0,1,2,),(p_(i),3k^(3),4k - 10k^(2),5k -1,):} Find the value of k.

The p.m.f. of a r.v. X is P(x)={{:(kx","x=1","2","3),(0", therwise"):} , then k =