The adjoining figure shows a square ABCD and an equilateral triangle DEC. Prove that :
(i) `angleADE=angleBCE=30^(@)`
(ii) `Delta cong DeltaBCE`

The adjoining figure shows a square ABCD and an equilateral triangle DEC. Prove that : (i) angleADE=angleBCE=30^(@) (ii) DeltaADE cong DeltaBCE

The following figure shows a square ABCD and an equilateral triangle DCE. Prove that : (i) angleADE=angleBCE=150^(@) (ii) DeltaADE cong DeltaBCE (iii) AE = BE

The following figure shows a square ABCD and an equilateral triangle DCE. Prove that : (i) angleADE=angleBCE=150^(@) (ii) DeltaADE cong DeltaBCE (iii) AE = BE

The given figure shows a square ABCD and an equilateral triangle ABP Calculate

The given figure shows a square ABCD and an equilateral triangle ABP Calculate:

The given figure shows a square ABCD and an equilateral triangle ABP. Calculate: angleAOB

The given figure shows a square ABCD and an equilateral triangle ABP. Calculate: anglePCD

The given figure shows a square ABCD and an equilateral triangle ABP. Calculate: angleBPC

ABCD is a square and DEC is an equilateral triangle. Prove that AE = BE.

ABCD is a square and DEC is an equilateral triangle. Prove that AE = BE.