If the distance of the point `P(1,-2,1)` from the plane `x+2y-2z=alpha,w h e r ealpha>0,i s5,` then the foot of the perpendicular from `P` to the place is a. `(8/3,4/3,-7/3)` b. `(4/3,-4/3,1/3)` c. `(1/3,2/3,(10)/3)` d. `(2/3,-1/3,-5/3)`

If the distance of the point P(1,-2,1) from the plane x+2y-2z=alpha, where alpha>0, is 5, then the foot of the perpendicular from P to the place is a.((8)/(3),(4)/(3),-(7)/(3)) b.((4)/(3),-(4)/(3),(1)/(3)) c.((1)/(3),(2)/(3),(10)/(3)) d.((2)/(3),-(1)/(3),-(5)/(3))

The foot of the perpendicular from (0,2,3) to the line (x+3)/5 = (y-1)/2 = (z+4)/3 is :

The foot of the perpendicular from the point P(1,3,4) to the plane 2x-y+z+3=0 is

The foot of the perpendicular from the point (1,2,3) to the line (x)/(2)=(y-1)/(3)=(z-1)/(3) is

The distance of the point (1, 2, -4) from the line (x-3)/(2)=(y-3)/(3)=(z+5)/(6) is

The perpendicular distance of the point (3,2,1) from the plane 3x+4y-2z - 10 = 0 is...............

Foot of the perpendicular drawn from the origin to the plane 2x - 3y + 4z = 29 is a) (5,-1,4) b) (7,-1,3) c) (5,-2,3) d) (2,-3,4)