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" (iii) "log(10)2+16log(10^(@))(16)/(15)...

" (iii) "log_(10)2+16log_(10^(@))(16)/(15)+12log_(10)(25)/(24)+7log_(10)(81)/(80)=1

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prove that log2+16log((16)/(15))+12log((25)/(24))+7log((81)/(80))=1

If 7"log"_(a)(16)/(15)+5"log"_(a)(25)/(24)+3"log"_(a)(81)/(80)=8 , then a=

7log((10)/(9))-2log((25)/(24))+3log((81)/(80))=log2

Givenlog (2)=0.3010 and log_(10)(3)=0.4771 find the value of 7log_(10)((10)/(9))-2log_(10)((25)/(24))+3log_(10)((81)/(80))

7log((10)/(9))-2log((25)/(24))+3log((81)/(80))

log_(10)((384)/(5))+log_(10)((81)/(32))+3log_(10)((5)/(3))+log_(10)((1)/(9))

show that 7log((16)/(15))+5log((25)/(24))+3log((81)/(80))=log2