दो रेखाओं `(x+1)/7=(y+1)/-6=(z+1)/1` तथा `(x-3)/1=(y-5)/-2=(z-7)/1` के बीच कि न्यूनतम दुरी ज्ञात कीजिये।

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

The Cartesian equation of two lines are (x+1)/7=(y+1)/-6=(z+1)/1 and (x-3)/1=(y-5)/-2=(z-7)/1 .Write the vector equations.

The Cartesian equation of two lines are given by (x+1)/7=(y+1)/-6=(z+1)/1,(x-3)/1=(y-5)/-2=(z-7)/1 Write the vector equation of these lines.

Find the shortest distance between the lines (x+1)/7=(y+1)/-6=(z+1)/1 and (x-3)/1=(y-5)/-2=(z-7)/1

Find the shortest distance between the lines (x+1)/7=(y+1)/(-6) =(z+1)/1 and (x-3)/1=(y-5)/-2=(z-7)/1

Find the shortest distance between the lines ((x+1)/7=(y+1)/-6=(z+1)/1 and (x-3)/1=(y-5)/-2=(z-7)/1)

Find the shortest distance between the lines ( x + 1 ) / ( 7 ) = ( y + 1 ) / ( - 6 )=(z+1)/1 and ( x - 3 ) / ( 1 ) = ( y - 5 ) / ( - 2 ) = ( z- 7 ) / ( 1 ) .