In a double slit experiment, at a certain point on the screen the path difference between the two interfering waves is `1/3 rd` of a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is:

At a certain point on a screen the path difference for the two interfering rays is (1//8)^(th) of a wavelength. Find the ratio of the intensity at this point to that at the centre of a bright fringe

In a Young's double slit experiment , the path difference at a certain point on the screen ,between two interfering waves is 1/8 th of wavelength.The ratio of the intensity at this point to that at the center of a bright fringe is close to :

In a Young's double slit experiment , the path difference at a certain point on the screen ,between two interfering waves is 1/8 th of wavelength.The ratio of the intensity at this point to that at the center of a bright fringe is close to :

In a Young's double slit experiment , the path difference at a certain point on the screen ,between two interfering waves is 1/8 th of wavelength .The ratio of the intensity at this point to that at the center of a bright fringe is close to :

The path of difference between two interfering waves at a point on the screen is (lambda)/(8) . The ratio of intensity at this point and that at the central fringe will be :

The path difference between two interfering waves of equal intensities at a point on the screen is lambda//4 . The ratio of intensity at this point and that at the central fringe will be

The path difference between two interfering waves of equal intensities at a point on the screen is lambda//4 . The ratio of intensity at this point and that at the central fringe will be