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Pressure versus temperature graph of an ...

Pressure versus temperature graph of an ideal gas is shown in figure. Density of the gas at point A is `rho_(0)`. Density at B will be

A

`(3)/(4)rho_(0)`

B

`(3)/(2)rho_(0)`

C

`(4)/(3)rho_(0)`

D

`2rho_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
According to ideal gas equation
`P=(rhoRT)/(M)orrho=(PM)/(RT)orrhoprop(P)/(T)`
From the graph,
`((P)/(T))_(A)=(P_(0))/(T_(0))and((P)/(T))_(B)=(3)/(2)((P_(0))/(T_(0)))`
or `((P)/(T))_(B)=(3)/(2)((P)/(T))_(A)" "therefore rho_(B)=(3)/(2)rho_(A)=(3)/(2)rho_(0)`
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