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The mean free path of molecules of a gas...

The mean free path of molecules of a gas (radius r) is inversely proportional to

A

`r^(3)`

B

`r^(2)`

C

r

D

`sqrt(r )`

Text Solution

Verified by Experts

The correct Answer is:
B
Mean free path, `lambda=(1)/(sqrt(2)npid^(2))`
where, n is the number density and d is the diameter of the molecule.
As `d=2r therefore lambda=(1)/(4sqrt(2)npir^(2))orlambdaprop(1)/(r^(2))`
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