The photoelectric threshold wavelength f...

The photoelectric threshold wavelength for silver is `lamda_(0)`. The energy of the electron ejected from the surface of silver by an incident wavelength `lamda(lamdaltlamda_(0))` will be

`hc(lamda_(0)-lamda)`

`(hc)/(lamda_0-lamda)`

`h/c((lamda_0-lamda)/(lamdalamda_0))`

`hc((lamda_0-lamda)/(lamdalamda_0))`

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The correct Answer is:

According to Einstein.s photoelectric equation
`K = (hc)/lamda-(hc)/lamda_0=hc(1/lamda-1/lamda_0)=hc ((lamda_0-lamda)/(lamdalamda_0))`

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