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The photoelectric work function for a me...

The photoelectric work function for a metal surface is `4.125 eV`. The cut - off wavelength for this surface is

A

`4500Å`

B

`1700Å`

C

`2800Å`

D

`3000Å`

Text Solution

Verified by Experts

The correct Answer is:
D
Work function , `phi_(0) = (hc)/ (lamda_0) " or " lamda_(0) = (hc)/(phi_0)`
Take `hc = 12400 eV Å`
`lamda_0=(12400 eVÅ)/(4.125eV) ~~3000Å`
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