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Light of frequency v falls on meterial o...

Light of frequency v falls on meterial of threshold frequency `v_(0)`. Maximum kinetic energy of emitted electron is proportional to

A

`upsilon - upsilon_0`

B

`upsilon`

C

`sqrt(upsilon - upsilon_0)`

D

` upsilon_0`

Text Solution

Verified by Experts

The correct Answer is:
A
According to Einstein.s photoelectric equation
`hupsilon=KE_(max) + phi_(0)`
But `phi_0 = h upsilon_(0) ,upsilon_0` being threshold frequency.
`:. KE_(max) = (hupsilon - hupsilon_0) or KE_(max) prop (hupsilon - hupsilon_0) `
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