A photon of wavelength `4400 Å` is passing through vaccum. The effective mass and momentum of the photon are respectively

Options

A. ` 5 xx 10^(-36) kg, 1.5 xx 10^(-27) kg ` m/s
B. ` 5 xx 10^(-35) kg, 1.5 xx 10^(-26) kg ` m/s
C. zero, `1.5 xx 10^(-26) ` kg m/s
D. ` 5 xx 10^(-36) kg, 1.67 xx 10^(-43) kgm//s`

Answer

A

Explanation

By de Brogie equation
Momentum ,
`p = h/lamda = (6.6 xx10^(-34))/(4400 xx 10^(-10))=1.5 xx10^(-27) kg m//s`
For photon, velocity `= c = 3 xx 10^(8) m/s`
`:. m = p/c=(1.5xx10^(-27))/(3 xx 10^8) " or " m = 5 xx 10^(-36) kg `
`:. m = 5 xx 10^(-36) , p = 1.5 xx 10^(-27) ` kgm/s