The de - Broglie wavelength of a particle moving with a velocity `2.25 xx 10^(8) m//s` is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is (velocity of light is `3 xx 10^(8) m//s`

Options

A. `1/8`
B. `3/8`
C. `5/8`
D. `7/8`

Answer

B

Explanation

`lamda = h/(mv)` is the de Broglie wavelength . The energy of a photon of this wavelength is
`K/E=(1/2mv^2)/(mvc) = (v)/(2c) = (2.25 xx10^8 )/(2xx(3 xx10^8))=(2.25 0)/6 =3/8`