An electron with speed v and a photon with speed c have the same de-Broglic wavelength. If the kinetic energy and momentum of electron is `E_(e)` and `P_(e)` and that of photon is `E_(ph)` and `P_(ph)` respectively, then correct statement is -

Options

A. `(E_e)/(E_(ph))=(2c)/v`
B. `(E_e)/(E_(ph))=v/(2c)`
C. `(P_e)/(P_(ph))=(2c)/v`
D. `(P_e)/(P_(ph))=(v)/(2c)`

Answer

B