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The ratio of wavelength of deutron and p...

The ratio of wavelength of deutron and proton accelerated through the same potential difference will be -

A

`1:2 `

B

`2:1`

C

`sqrt2 : 1 `

D

`1 : sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda=(h)/sqrt(2qVm)`
Since both proton and deuteron have same charge and accelerated through the same potential difference .
`:. lamda prop 1/sqrtm :. lamda_p/lamda_d = sqrt((m_d)/(m_p)) = sqrt((2m_p)/m_p) = sqrt2`
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