The kinetic energy of an electron gets tripled, then the de-Broglie wavelength associated with it changes by a factor

Options

A. `1/3`
B. `sqrt3 `
C. `1/sqrt3`
D. 3

Answer

C

Explanation

For an electron,
de Broglie wavelength , `lamda = h/(sqrt(2mK))`
where, h = Plank.s constant , m = mass of an electron, Since m remains the same ,
`:.lamda prop 1/sqrtK`
`implies lamda/(lamda.)=sqrt((K.)/K) = sqrt((3K)/K)" or " lamda. = lamda/sqrt3`