`lambda_(e),lambda_(p)` and `lambda_(alpha)` are the de-Broglie wavelength of electron, proton and `alpha` particle. If all the accelerated by same potential, then

Options

A. `lamda_(e) lt lamda_(p) lt lamda_(alpha)`
B. `lamda_(e) lt lamda_(p) gt lamda_(alpha)`
C. `lamda_(e) gt lamda_(p) lt lamda_(alpha)`
D. `lamda_(e) gt lamda_(p) gt lamda_(alpha)`

Answer

D

Explanation

de Broglie wavelength , `lamda = h/(sqrt(2mqV))`
For the same value of V
or `lamdaprop1/sqrt(mq)`
`:. lamda_(e) : lamda_p : lamda_(alpha) = 1/sqrt(m_eq_e):1/sqrt(m_pq_p): 1/sqrt(m_alphaq_alpha)`
`=1/(sqrt(((m_p)/(1840))xxe)):1/(sqrt(m_pxxe)):1/(sqrt(4m_pxx2e))`
`:. lamda_(e) gt lamda_p lt lamda_(alpha)`