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A praticle of mass M at rest decays into...

A praticle of mass M at rest decays into two particle of masses `m_1` and `m_2`, having non-zero velocities. The ratio of the de Broglie wavelength of the particles `(lamda_1)/(lamda_2)` is

A

`m_1/m_2`

B

`m_2/m_1`

C

`1:1`

D

`sqrt((m_1)/(m_2))`

Text Solution

Verified by Experts

The correct Answer is:
C
If `v_1 and v_2` are the velocities of two mases `m_1 and m_2` then , according to conservation of momentum
`M xx 0 = m_(1) v_(1) + m_(2)v_2`
or `m_1v_1=-m_2v_2= m_2v_2=m_2v_2` (in magnitude)
`:. (lamda_1)/(lamda_2)=(h//m_1v_1)/(h//m_2v_2)=1`
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