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The de Broglie wavelength is given by...

The de Broglie wavelength is given by

A

`p= (2pih)/lamda`

B

`p = (h)/(2lamda)`

C

`p = (2pi)/(hlamda)`

D

`p = (2pi)/lamda`

Text Solution

Verified by Experts

The correct Answer is:
A
de Broglie wavelength is given by
`lamda= h/p` , where p is the momentum or `p = h/lamda`
Since , `h = h/(2pi) :. P = (2pih)/(lamda)`
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MTG GUIDE-DUAL NATURE OF MATTER AND RADIATION -NEET Cafe Topicwise Practice Questions (MATTER WAVES AND DE BROGLIE RELATION)
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