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Radiations of frequencies `v_1 and v_2` are made to fall in turn, on a photosensitive surface. The stopping potential required for stopping the most energetic photoelectrons in the two cases are `V_1 and V_2` respectively. Obtain a formula for determining the threshold frequency in terms of these parameters.

A

`(e(V_1+V_2))/(upsilon_(1)+upsilon_(2))`

B

`(e(V_1-V_2))/(upsilon_(1)+upsilon_(2))`

C

`(e(V_2-V_1))/(upsilon_(2)-upsilon_(1))`

D

`(e(V_1-V_2))/(e(upsilon_(2)-upsilon_(1)))`

Text Solution

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The correct Answer is:
C
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