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If (x + 2)(x + 3b) = c has roots alpha,b...

If (x + 2)(x + 3b) = c has roots `alpha,beta` , then the roots of `(x + alpha)(x+beta) + c = 0` are

A

a,b

B

-a, -b

C

-2, -3b

D

2a, 3b

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The correct Answer is:
D
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