Home
Class 12
BIOLOGY
Catalytic action of a multienzyme comple...

Catalytic action of a multienzyme complex, involving six different co-factors, is needed for the formation of

A

Acetyl phosphate

B

Acetyl Co. A

C

Pyruvic acid

D

a-Ketoglutaric acid

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • RESPIRATION IN PLANTS

    AAKASH SERIES|Exercise Exercise-I (Respiratory Quotient)|18 Videos
  • RESPIRATION IN PLANTS

    AAKASH SERIES|Exercise Exercise-II|27 Videos
  • RESPIRATION IN PLANTS

    AAKASH SERIES|Exercise Exercise-I (Fermentation)|18 Videos
  • PRINCIPLES OF INHERITANCE AND VARIATION

    AAKASH SERIES|Exercise EXERCISE -III (Previous AIPMT /NEET Questions)|39 Videos
  • TRANSPORT IN PLANTS

    AAKASH SERIES|Exercise EXERCISE III|20 Videos

Similar Questions

Explore conceptually related problems

Explain different types of co-factors.

The factors involved in the formation of new species are

How are prosthetic groups different from co-factors ?

The central metal ion in the complex makes available a number of empty orbitals for the formation of co-ordinate bonds with suitable ligands. The inner d-orbitals or outer d-orbitals are involved. The empty hybrid orbitals of metal ion overlap with the filled orbitals of ligand to from metal ligand co-ordinate bonds. For co-ordination number 6 octahedral geometry and sp^(3),d^(2)ord^(2)sp^(2) hybridisation involved and for cordiantion number 4 tetrahedral geometry, square planar geometry and sp^(3).dsp^(2) hybridisation involved. Type of complex formed in [Fe(H_(2)O)_(6)]^(+3) ion

The central metal ion in the complex makes available a number of empty orbitals for the formation of co-ordinate bonds with suitable ligands. The inner d-orbitals or outer d-orbitals are involved. The empty hybrid orbitals of metal ion overlap with the filled orbitals of ligand to from metal ligand co-ordinate bonds. For co-ordination number 6 octahedral geometry and sp^(3),d^(2)ord^(2)sp^(2) hybridisation involved and for cordiantion number 4 tetrahedral geometry, square planar geometry and sp^(3).dsp^(2) hybridisation involved. Geometry of [Ni(CN)_(4)]^(-2) ion is

The central metal ion in the complex makes available a number of empty orbitals for the formation of co-ordinate bonds with suitable ligands. The inner d-orbitals or outer d-orbitals are involved. The empty hybrid orbitals of metal ion overlap with the filled orbitals of ligand to from metal ligand co-ordinate bonds. For co-ordination number 6 octahedral geometry and sp^(3),d^(2)ord^(2)sp^(2) hybridisation involved and for cordiantion number 4 tetrahedral geometry, square planar geometry and sp^(3).dsp^(2) hybridisation involved. Hybridisation present in [Cr(NH_(3))_(6)]^(+3)

The d-orbitals participating in hybridisation of metal atom may be from the n & (n-1) shell. This depends on the nature of metal and nature of ligand. The complexes involving the inner d-level (inner orbital complexes) results when the ligand is a powerful (or) strong ligand results in a diamagnetic (or) low spin complexes. A weak ligand usually results in the formation of outer orbital complex (or) high spin complex. Among the following sets, the one having the same geometry and same magnetic property for both complexes is

The d-orbitals participating in hybridisation of metal atom may be from the n & (n-1) shell. This depends on the nature of metal and nature of ligand. The complexes involving the inner d-level (inner orbital complexes) results when the ligand is a powerful (or) strong ligand results in a diamagnetic (or) low spin complexes. A weak ligand usually results in the formation of outer orbital complex (or) high spin complex. Number of unpaired electrons present in [Fe(CN)_(6)]^(4-)&[Fe(H_(2)O)_(6)]^(2+) are respectively.

The d-orbitals participating in hybridisation of metal atom may be from the n & (n-1) shell. This depends on the nature of metal and nature of ligand. The complexes involving the inner d-level (inner orbital complexes) results when the ligand is a powerful (or) strong ligand results in a diamagnetic (or) low spin complexes. A weak ligand usually results in the formation of outer orbital complex (or) high spin complex. The hybridisation of Cu in [CuCl_(4)]^(2-)&[Cu(NH_(3))_(4)]^(2+) are respectivly

AAKASH SERIES-RESPIRATION IN PLANTS-Exercise-I (Aerobic respiration (ETS , BS , Amphibolic)
  1. The incomplete breakdown of sugars in anaerobic respiration results in...

    Text Solution

    |

  2. Which of the following reactions takes place in the matrix of the cell...

    Text Solution

    |

  3. Catalytic action of a multienzyme complex, involving six different co-...

    Text Solution

    |

  4. Though mitochondria are absent in the cells, Tricarboxylic acid cycle ...

    Text Solution

    |

  5. How many oxygen atoms are required for Respiratory electron transport,...

    Text Solution

    |

  6. The dicarboxylic acid required for the formation of first Tricarboxyli...

    Text Solution

    |

  7. Product of first biological oxidation in Krebs cycle is

    Text Solution

    |

  8. When one molecule of Glucose is completely oxidized in aerobic respira...

    Text Solution

    |

  9. Calculate the number of ATP produced for one Glyceraldehyde 3-phosphat...

    Text Solution

    |

  10. The substrate for final decarboxylation reaction of aerobic respiratio...

    Text Solution

    |

  11. Number of ATP generated in ETS on oxidation of reduced Co-enzymes prod...

    Text Solution

    |

  12. Number of ATP molecules formed through oxidative decarboxylation react...

    Text Solution

    |

  13. The correct sequence of electron carriers (Cytochromes) in Respiratory...

    Text Solution

    |

  14. ATP is a

    Text Solution

    |

  15. Non-mitochondrial aerobic respiration occurs in

    Text Solution

    |

  16. The ATP output of aerobic respiration is more than that of anaerobic r...

    Text Solution

    |

  17. The number of oxidations, substrate level phosphorylations respectivel...

    Text Solution

    |

  18. Pick out the correct statement from following

    Text Solution

    |

  19. The substrates of 1^(st) oxidation and 4^(th) oxidation of Krebs cycle...

    Text Solution

    |

  20. The 5C-intermediate of Krebs cycle that serves as substrate for transa...

    Text Solution

    |