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For what value of k will k + 9, 2k - 1, ...

For what value of `k` will `k + 9, 2k - 1, 2k + 7` be consecutive terms of a AP.

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The correct Answer is:
`2k + 7 - (2k -1) = (2k -1)- (k+ 9)`
`6= k-8 rArr k = 14`.
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