Home
Class 10
MATHS
Find the sum of all natural numbers betw...

Find the sum of all natural numbers between 1 and 1000 which are divisible by 3,

Text Solution

Verified by Experts

The correct Answer is:
`= (33)/(2) [ 3+ 999] = (333xx 1002)/(2)= 166833`.
Promotional Banner

Topper's Solved these Questions

  • ARITHMETIC PROGRESSIONS

    ZEN PUBLICATION|Exercise ZEN ADDITIONAL QUESTIONS (LONG-ANSWER [LA] TYPE - QUESTIONS)|14 Videos

  • ARITHMETIC PROGRESSIONS

    ZEN PUBLICATION|Exercise ZEN ADDITIONAL QUESTIONS (HOTS [HIGHER ORDER THINKING SKILLS] - QUESTIONS)|4 Videos

  • ARITHMETIC PROGRESSIONS

    ZEN PUBLICATION|Exercise ZEN ADDITIONAL QUESTIONS (SHORT-ANSWER [SA] TYPE 1 - QUESTIONS)|24 Videos

  • AREA RELATED TO CIRCLES

    ZEN PUBLICATION|Exercise ADDITIONAL QUESTIONS (HIGHER ORDER THINKING SKILLS)|7 Videos

  • CIRCLES

    ZEN PUBLICATION|Exercise ZEN ADDITIONAL QUESTIONS ( HOT [HIGHER ORDER THINKING SKILLS] - QUESTIONS) (IIT AND IMO)|9 Videos

Similar Questions

Explore conceptually related problems

Find the sum of all natural numbers between 1 and 201 which are divisible by 5.

Find the sum of all natural numbers between 200 and 300 which are divisible by 6.

Find the sum of all natural numbers between 50 and 500, which are divisible by 6.

Find the sum of all numbers between 200 and 400 which are divisible by 7?

Find the 60th term of an A.P 8, 10 , 12, .....if it has a total of 60 terms and hence find the sum of its last 10 terms. OR Find the sum of all natural numbers between 200 and 300 which are exactly divisible by 6.

Find the sum of all natural numbers lying between 100 and 1000 , which are multiples of 5.

Find the sum of the odd numbers between 0 and 50.

Find the sum of first n odd natural numbers.

Find the sum of natural odd numbers from 1 to 100.