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Draw the graphs of the equations x-y+1=0...

Draw the graphs of the equations `x-y+1=0" and "3x+2y-12=0`. Determine the co-ordinates of the vertices of the triangle formed by these lines and the x-axis and shade the triangular region.

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The correct Answer is:
The lines intersect at p(2, 3); hence x = 2 and y = 3 is the solution of the given pair of equations. The triangle formed is APB: A(-1,0), B(4,0), P(2,3).
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Knowledge Check

  • Orthocentre of the triangle formed by the lines x+y=1 and x y=0 is

    A
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    B
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    C
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    D
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    D
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  • The area of the triangle formed by the lines y = x, x = 6, and y = 0 is

    A
    72 square units
    B
    36 square units
    C
    18 square units
    D
    9 square units

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