In the figure, an isosceles triangle ABC with `AB=AC` circumscribes a circle. Prove that the point of contact P bisects the base BC.

Quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB+CD=AD+BC .

In the figure, a triangle ABC is drawn to circumscribe a circle of radius 2 cm such that the segments BD and DC into which BC is divided by the point of contact are the lengths 4 cm and 3 cm respectively. If the area of DeltaABC=21 cm^(2) , find the length of sides AB and AC.

ABC is an isosceles triangle with AB = AC. Draw AP _|_ BC to show that A = B.

In an isosceles triangle ABC with AB = AC, D and E are points on BC such that BE = CD (see figure) Show that AD = AE

In an isosceles triangle ABC, if AB = AC = 25 cm and altitude from A on BC is 24 cm, find BC.

A quadrilateral ABCD is drawn to circumscribe a circle as shown. Prove that AB+CD=AD +BC.

In an isosceles triangle ABC, with AB = AC, the bisectors of /_ B and /_ C intersect each other at O. Join A to O. Show that : (i) OB = OC (ii) AO bisects /_A

If an isosceles DeltaABC in which AB=AC=6cm is inscribed in a circle of radius 9 cm, find the area of the triangle.

AD is an altiude of an isosceles triangle ABC in which AB = AC. Show that (i) AD bisects BC (ii) AD bisects A.