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Write the values of sec0^(@), sec 30^(@)...

Write the values of `sec0^(@), sec 30^(@), sec 45^(@), sec 60^(@)` and `sec 90^(@)`. What happens to `sec x` when `x` increases from `0^(@)` to `90^(@)` ?

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The correct Answer is:
The value of `sec x` increases and reaches a not-defined value as `x` increases from `0^(@)` to `90^(@)`.
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