The bob of pendulum of length l is pulled aside from its equilibrium position through an angle `theta` and then released. Find the speed v with which the bob passes through the equilibrium position.

The bob of a simple pendulum of length 1 m is' pulled aside from its equilibrium’ position through an angle 60^@ and released. Calculate the speed at which the bob passes the equilibrium position.

The bob of a pendulum of length l is pulled aside from its equilibrium position through an angle theta and then released. The bob will then pass through its equilibrium position with a speed v, where v equals

Show that a simple pendulum bob which has been pulled aside from its equilibrium position through an angle theta and the released will pass through an equilibrium position with speed v=sqrt(2gl(1-cos theta)) , where/is the length of the pendulum.

A pendulum bob of mass m is displaced through an angle theta from its equilibrium position and then released. What will be the tension in the string when the bob crosses the equilibrium position?

The figure shows a pendulum of length l suspended at a distance x vertically above a peg. (a) The pendulum bob is deflected through an angle theta and then released. Find the speed of the bob at the instant (b) The pendulum is released when theta = 90^(@) . For what x (position of peg) will the pendulum complete the circle ? (c) The pendulum is released when theta = 60^(@) . what is the velocity of the bob as it passes position E.

A mass at the end of a spring executes harmonic motion about an equilibrium position with an amplitude A.Its speed as it passes through the equilibrium position is V.If extended 2A and released, the speed of the mass passing through the equilibrium position will be