The differential equation of a particle undergoing SHM is given
by a `a(d^(2)"x")/(dt^(2))+b"x"=0`. The particle starts from the extreme position.
The ratio of the maximum acceleration to the maximum velocity of the particle is –

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is

The differential equation of a particle undergoing SHM is given by a a(d^(2)"x")/(dt^(2))+b"x"=0 ltbr.gt The particle starts from the extreme position The equation of motion may be given by :

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The time period of osciallation is given by

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The time period of osciallation is given by

Obtain the ratio of maximum acceleration and maximum velocity of a SHM particle.

The ratio of maximum acceleration to the maximum velocity of a particle performing S.H.M. is equal to

The differential equation of a particle performing a S.H.M. is (d^(2)x)/(dt^(2))+ 64x=0 . The period of oscillation of the particle is

Where is maximum acceleration and zero velocity of a particle axecuting SHM?