" (ii) "a sin(B-C)/(2)=(b-c)cos(A)/(2)

For any triangle ABC, prove that : sin""(B-C)/(2)=(b-c)/(a)cos((A)/(2))

For any triangle ABC, prove that (sin(B-C))/(2)=(b-c)/(a)((cos A)/(2))])

For any DeltaABC , prove that sin ((B-C)/2)=(b-c)/a cos (A/2)

In any triangle ABC prove that: sin((B-C)/(2))=((b-c)/(a))(cos A)/(2)

In any triangle ABC, prove that following: sin((B-C)/(2))=(b-c)/(a)(cos A)/(2)

In any triangle A B C , prove that following: sin((B-C)/2)=(b-c)/a cos (A/2)

If a ,b ,c denote the lengths of the sides of a triangle opposite to angles A ,B ,C respectively of a A B C , then the correct relation among a ,b , cA ,Ba n dC is given by (b+c)sin((B+C)/2)=acos b. (b-c)cos(A/2)=asin((B-C)/2) c. (b-c)cos(A/2)=2asin((B-C)/2) d. (b-c)sin((B-C)/2)="a c o s"A/2

In triangle ABC,a,b,c are the lengths of its sides and A,B,C are the angles of triangle ABC .The correct relation is given by (a) (b-c)sin((B-C)/(2))=a(cos A)/(2) (b) (b-c)cos((A)/(2))=as in(B-C)/(2)(c)(b+c)sin((B+C)/(2))=a(cos A)/(2)(d)(b-c)cos((A)/(2))=2a(sin(B+C))/(2)

In any triangle ABC, prove that (i) (a-b)/( c)=("sin"(A-B)/(2))/("cos"( C)/(2)) (ii) (b-c)/(a)=("sin"(B-C)/(2))/("cos"(A)/(2))