When 2.56 g of sulphur is dissolved in 100 g of `CS_(2)`, the freezing point of the solution gets lowerd by 0.383 K. Calculate the formula of sulphur `(S_(x))`. [Given `K_(f)` for `CS_(2)=3.83` "K kg mol"^(-1)`], [Atomic mass of sulphur=32g `mol^(-1)`]

(a) When 2.56 g of sulphur was dissolved in 100 g of CS_(2) , the freezing point lowered by 0.383 K. Calculate the formula of sulphur (S_(x)) . ( K_(f) for CS_(2) = 3.83 K kg mol^(-1) , Atomic mass of sulphur = 32g mol^(-1) ] (b) Blood cells are isotonic with 0.9% sodium chloride solution. What happens if we place blood cells in a solution containing. (i) 1.2% sodium chloride solution? (ii) 0.4% sodium chloride solution?

When 2.56 g of sulphur was dissolved in 100 g of CS_(2) , the freezing point lowered by 0.383 K. Calculate the formula of sulphur (S_(x)) . ( K_(f) for CS_(2) = 3.83 K kg mol^(-1) , Atomic mass of sulphur = 32g mol^(-1) ]

When 2.56g of sulphur was dissolved in 100 g of CS_2 , the freezing point lowered by 0.383K. Calculate the formula of sulphur (S_x) . (k_(f) for CS_2 = 3.83K kg mol^-1 , Atomic mass of sulphur = 32g mol^-1) .

On dissolving 3.24 g of sulphur in 40 g of benzene,the boiling point of the solution was higher than that of benzene by 0.81K .What is the molecular formula of sulphur? ( K_(b) for benzene = 2.53 K kg mol^(-1) , atomic mass of sulphur = 32 g mol^(-1) ).

3g urea is dissolved in 100ml water. Find the freezing point of solution ( K_f = 1.86k kg mol_(-1) )

1.00g of non - electrolyte dissolved in 100 g of CS_(2) , the freezing point lowered by 0.40 K. Find the molar mass of the solute . ( k_(f) for CS_(2) = 5.12 K kg mol^(-1) ).

3.795 g of sulphur is dissolved in 100g of CS_(2) . This solution boils at 319.81 K. What is the molecular formula of sulphur in solution? The boiling point of CS_(2) is 319.45 kJ (Given that K_(b) for CS_(2) = 2.42 K kg mol^(-1) and atomic mass of S = 32)

A solution containing 25.6 g of sulphur, dissolved in 1000 g of naphthalene whose melting point is 80.1^(@)C gave a freezing point lowering of 0.680^(@)C . Calculate the formula of sulphur ( K_(f) for napthalene = 6.8 K m^(-1) )