The masses `(M+m)` and `(M-m)` are attached to the ends of a light inextensible string and the string is made to pass over the surface of a smooth fixed pulley. When the masses are relased from rest the acceleraion of the system is .

Two masses M and m are connected at the two ends of an inextensible string. The string passes over a smooth frictionless pulley. Calculate the acceleration of the masses . Given M > m.

Two uneqal masses of 1 kg and 2 kg are attached at the two ends of a light inextensible string passing over a smooth pulley as shown . If the system is released from rest, find the work done by string on both the blocks in 1 s. (Take g= 10 m//s^2 ).

Two unequal masses of 1 kg and 2 kg are attached at the two ends of a light inextensible string passing over a smooth pulley as shown . If the system is released from rest, find the work done by string on both the blocks in 1 s. (Take g= 10 m//s^2 ).

The masses M and m connected to the two ends of an inextensible string. The string passes over a smooth frictionless pulley. Calculate the acceleration of the masses and the tension in the string. Given, M gt m .

Two masses M and m are connected at the two ends of an inextensible string. The string passes over a smooth frictionless pulley. Calculate the acceleration of the masses and the tension in the string. Given Mgtm .

Two particles of mass m_(1) and m_(2)(m_(1) gt m_(2)) are attached to the ends of a light inextensible string passing over a smooth fixed pulley. When the level of m_(1) is higher than that of m_(2) by 49 cm and string is just taut m_(2) is released. 0.5 s after motion started the masses are at the same level. the ratio of m_(1) to m_(2) is (Take g=9.8ms^(-2) )

Two masses M_(1)=5kg,M_(2)=10 kg are connected at the ends of an inextensible string passing over a frictionless pulley as shown. When masses are released, then acceleration of masses will be