" (iv) "CM=(1)/(2)AB

ABC is a triangle right angled at C. A line through the midpoint M of hypotenuse AB and Parallel to BC intersects AC at D. Show that (i) D is the midpoint of AC (ii) MD_|_AC (iii) CM=MA=(1)/(2)AB.

ABC is a triangle right angled at C. A line through the midpoint M of hypotenuse AB and Parallel to BC intersects AC at D. Show that (i) D is the midpoint of AC (ii) MD_|_AC (iii) CM=MA=(1)/(2)AB.

ABC is a triangle right angled at C. A line through the midpoint M of hypotenuse AB and Parallel to BC intersects AC at D. Show that (i) D is the midpoint of AC (ii) MD_|_AC (iii) CM=MA=(1)/(2)AB.

ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that CM=MA=1/2AB

ABC is a triangle right angled at C. A line through the mid points M of hypotenuse AB and parallel to BC intersects AC at D. Show that D is the mid point of AC MD bot AC CM=MA=1/2AB

In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (See Fig. ) Show that : CM=1/2AB .

In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (See Fig.) Show that : CM=1/2AB .

ABC is a triangle right angled at 'C'. A line through the midpoint M of hypotenuse AB and parallel to BC intersects AC at D. Show that : CM = MA = 1/2 AB .

In right triangle ABC, right angle is at 'C'. M s the mid-point of hypotenuse . ABC is joined to M and produced to a point D such that DM = CM. Point D is Joined to point B (see fig.). Show that: CM=1/2AB