Consider the circles `x^(2) + y^(2) = 1` & `x^(2) + y^(2) – 2x – 6y + 6 = 0`. Then equation of a common tangent to the two circles is

If (-(1)/(3),-1) is a centre of similitude for the circles x^(2)+y^(2)=1 and x^(2)+y^(2)-2x-6y-6=0, then the length of common tangent of the circles is

If (-1/3-1) is a centre of similitude for the circles x^(2)+y^(2)=1 and x^(2)+y^(2)_2x-6y-6=0 then the length of common tangent of the circles is

P(-1,-3) is a centre of similitude of for the two circles x^(2)+y^(2)=1 and x^(2)+y^(2)-2x-6y+6=0 . The length of the common tangent through P to the circles is

If (-1/3,-1) is a centre of similitude for the circles x^2+y^2=1 and x^2+y^2-2x-6y-6=0 , then the length of common tangent of the circles is

If (2,6) is a centre fo similitude for the circle x^(2)+y^(2)=4 and x^(2)+y^(2)-2x-6y+9=0 , the length of the common tangent of circles through is

The two circles x^2 +y^2-2x+6y+6=0 and x^2 +y^2-5x+6y+15=0 touch each other. The equation of their common tangent is

Statement 1 : The number of common tangents to the circles x^(2) + y^(2) =4 and x^(2) + y^(2) -6x - 6y = 24 is 3. Statement 2 : If two circles touch each other externally thenit has two direct common tangents and one indirect common tangent.

Statement 1 : The number of common tangents to the circles x^(2) + y^(2) =4 and x^(2) + y^(2) -6x - 6y = 24 is 3. Statement 2 : If two circles touch each other externally thenit has two direct common tangents and one indirect common tangent.