When a capillary tube is dipped in a liquid, the liquid rises to a height h in the tube. The free liquid surface inside, the tube is hemispherical in shape. The tube is now pushed down so that the height of the tube outside the liquid is less than `h`. Then

If a capillary tube is dipped and the liquid levels inside and outside the tube are same. Then the angle of contact is

If a capillary tube is dipped and the liquid levels inside and outside the tube are same. Then the angle of contact is

When a capillary tube of radius 'r' is dipped vertically in a liquid of surface tension T, the liquid rises to a height 'h' in the tube above the level outside the tube. If the angle of contact is theta , the density of the liquid is rho , then the pressure difference is.

When a capillary tube of radius r is dipped vertically in a liquid of surface tension T, the liquid rises to a height h in the tube above the level outside the tube . If the angle of contact is theta the density of the liquid is rho then the pressure difference between the points A and B is

When a capillary tube of radius r is immersed in a liquid of density rho, the liquid rises to a height h in it. If m is the mass of the liquid in the capillary tube, find the potential energy of this mass of the liquid in the tube.

When two capillary tubes of different diameters are dipped vertically in a liquid, the height of the liquid is:

When a capillary tube is dipped in a liquid, it rises in the tube to a height h above the outside level . What would happen it the tube is dipped such that its length outside the liquid is less then h? Explain your answer briefly.