A body executes simple harmonic motion under the action of a force `F_1` with a time period `4/5 s`. If the force is changed to `F_1` and `F_2` it executes SHM with time period `3/5` s .If the both the forces `F_1` and `F_2` act simultaneously in the same direction on the body, its time period in seconds is,

A body executes simple harmonic motion under the action of a force F_1 with a time period (4)/(5)s . If the force is changed to F_(2) , it executes SHM with time period (3)/(5)s . If both the forces F_(1) and F_(2) act simultaneously in the same direction on the body, its time period (in seconds) is

A body executes simple harmonic motion under the action of a force F_1 with a time period (4)/(5)s . If the force is changed to F_(2) , it executes SHM with time period (3)/(5)s . If both the forces F_(1) and F_(2) act simultaneously in the same direction on the body, its time period (in seconds) is

A particle is executing simple harmonic motion under the action of a force F with a time period (3)/(5) s. When the force is changed to F' , the time period of oscillation is (4)/(5) s. When both the forces F and F' act simultaneously in the same direction on the body, time period in seconds in T = (6a)/(5b) . COmpute the value of a + b.

A body is executing simple harmonic motion under the action of a force F_(1) with time period 1 s. The time period is 2s when body is acted by another force F_(3) . What will be the total time period when both the forces are acting in same direction simultaneously ?

Due to some force F_(1) a body oscillates with period 4//5s and due to other force F_(2) it oscillates with period 3//5s . If both the forces acts simultaneously in same direction then new period is

A body executes SHM under the influence of one force and has a period T_1 seconds and the same body executes SHM with period T_2 seconds when under the influence of another force. When both forces act simultaneously and in the same direction, then the time period of the same body (in seconds) is: