An engine pumps up 1 quintal of coal from a coal mine 100 m deep in 0.5 seocnd. If its efficienty is 60% then the power of the engine is
(take `g=10m//s^(2))`

An engine pumps up 100 kg water through a height of 10 m in 5 s . If efficiency of the engine is 60% . What is the power of the engine? Take g = 10 ms^(2) .

An engine pumps up 100 kg water through a height of 10 m in 5 s . If effcienecy of the engine is 60% . What is the power of the engine? Take g = 10 ms^(2) .

A pump can throw up 10 quntals of coal per hour from a coal mine 120m deep. Calculate the power of the engine in watt assuming that efficiency is 80% .

An engine pumps 373 kg of water upto height of 16 m in 40 seconds. Rated power of engine if its efficiency is 80% is (1 horse power = 746 W and g =10 m/ s^2 )

An engine pumps 373 kg of water upto height of 16 m in 40 seconds. Rated power of engine if its efficiency is 80% is (1 horse power = 746 W and g=10 m/s^2 )

If a rubber ball is taken to 100 m deep in a lake and its volume changes by 0.1% then the bulk modulus of rubber will be (g=10m//s^(2))

An engine of weight 6.5 metric ton is going up an inclined plane of 5 in 13 at the rate of 9km//h . If the coefficient of friction is (1)/(120 . Calculate the power of the engine. Take g=9.8m//s^(2)