`6x - 5 lt 7`

Solve |5x - 7| lt -18 .

If x satisfies the inequations 2x - 7 lt 11 , 3x + 4 lt -5 , then x lies in the interval

If 6x -= 5 (mod 7), then find x.

A = {x : 2 lt x lt 8 " and " x in N} and B = {x:3 lt x lt 9 " and " x in W} . Find (A - B) nn (B - A) . the following are the steps involved n solving the above problem. Arrange them in sequential order. (A) A = {3,4,5,6,7} and B = {4,5,6,7,8} (B) A - B = {3}, B - A = {8} (C) A - B = {3,4,5,6,7}-{4,5,6,7,8}, B-A ={4,5,6,7,8} - {3,4,5,6,7} (D) (A - B) nn (B - A) = phi

Number of intergral value of x satisfying the inequality (x^(2) + 6x - 7)/(|x + 4|) lt 0 is :

Number of intergral value of x satisfying the inequality (x^(2) + 6x - 7)/(|x + 4|) lt 0 is :

The set of values of x satisfying 2 le abs(x-3) lt 4 is : a) (-1, 1] cup [5, 7) b) -4 le x le 2 c) -1 lt x lt 7 or x ge 5 d) x lt 7 or x ge 5