If the papers of 4 students can be checked by any one of the 7 teachers, then the probability that all the 4 papers are checked by exactly 2 teachers is a.`2//7` b. `12//49` c. `32//343` d. none of these

If the papers of 4 students can be checked by any one of the 7 teachers, then the probability that all the 4 papers are checked by exactly 2 teachers is 2//7 b. 12//49 c. 32//343 d. none of these

If the papers of 4 students randomly distributed for checking among 7 teacher, then the probability that all the 4 papers are checked by exactly 2 teachers is n/m where n, m are natural number and HCF(n,m)=1 . Then number of positive divisiors of (n+m) is

If the papers of 4 students randomly distributed for checking among 7 teacher, then the probability that all the 4 papers are checked by exactly 2 teachers is n/m where n, m are natural number and HCF(n,m)=1 . Then number of positive divisiors of (n+m) is

If the papers of 4 students randomly distributed for checking among 7 teacher, then the probability that all the 4 papers are checked by exactly 2 teachers is n/m where n, m are natural number and HCF(n,m)=1 . Then number of positive divisiors of (n+m) is

If the papers of 4 students randomly đistributed for checking among 7 teachers, then the probability that all the 4 papers are checked by exactly 2 teachers is n i m where n, m are 'natural numbers and H C F(n, m)=1 . Then number of positive divisors of (n+m) is

The probability that a certain kind of component will survive a check test is 0.6 Find the probability that exactly 2 of the next 4 rested componentws suvive.