If `(sin(alpha+beta))/(sin(alpha-beta)) = (a+b)/(a-b)`, then prove that a `tan beta = b tan alpha`.

(sin(alpha+beta))/(sin(alpha-beta))=(a+b)/(a-b) then (tan alpha)/(tan beta)=

(sin (alpha + beta)) / (sin (alpha-beta)) = (a + b) / (ab) rArr (tan alpha) / (tan beta) =

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

If sin(alpha+beta)=1,sin(alpha-beta)=(1)/(2) then tan(alpha+2 beta)tan(2 alpha+beta)=

Show that (sin (alpha + beta))/( sin (alpha + beta)) = 2, given that tan alpha = 2 tan beta.

If : sin (alpha + beta)=1 and sin (alpha-beta)=(1)/(2), "then" : tan (alpha+2beta)*tan(2alpha+beta)= A)-1 B)0 C)1 D)2

If : sin (alpha + beta)=1 and sin (alpha-beta)=(1)/(2), "then" : tan (alpha+2beta)*tan(2alpha+beta)=

if tan beta=(n sin alpha cos beta)/(1-n sin^(2)alpha) then prove that tan(alpha-beta)=(1-n)tan alpha

if tan beta=(n sin alpha cos beta)/(1-n sin^(2)alpha) then prove that tan(alpha-beta)=(1-n)tan alpha