The torque `vec tau` on a body about a given point is found to be equal to `vec A xx vec L` where `vec A` is a constant vector and `vec L` is the angular momentum of the body about the point. From this its follows that -

The torque tau on a body about a given point is found to be equal to AxxL where A is a constant vector, and L is the angular momentum of the body about that point. From this it follows that

The torque tau on a body about a given point is found to be equal to A x L, where A is constant vector and L is the angular momentum of the body that point. From this, it follows that

Torque (vec tau) acting on a rigid body is defined as vec tau = vec A xx vec L , where vec A is a constant vector and vec L is angular momentum of the body. The magnitude of the angular momentum of the body remains same. vec tau is perpendicular to vec L and hence torque does not deliver any power to the body.

A force vec F = 3 vec i + 2 vec j - 4 vec k is acting at the point (1,-1, 2) . Find the vector moment of vec F about the point (2,-1,3) .

If vec(tau)xxvec(L)=0 for a rigid body, where vec(tau)= resultant torque & vec(L) =angular momentum about a point and both are non-zero. Then

If vec(tau)xxvec(L)=0 for a rigid body, where vec(tau)= resultant torque & vec(L) =angular momentum about a point and both are non-zero. Then

If vec F is the force acting in a particle having position vector vec r and vec tau be the torque of this force about the origin, then