If `intsinx d(secx)=f(x)-g(x)+c ,t h e n` `f(x)=secx` (b) `f(x)=tanx` `g(x)=2x` (d) `g(x)=x`

"If " int sinx d(secx)=f(x)-g(x)+c, then

"If " int sinx d(secx)=f(x)-g(x)+c, then

"If " int sinx d(secx)=f(x)-g(x)+c, then

If int sin xd(sec x)=f(x)-g(x)+c, then f(x)=sec x( b )f(x)=tan xg(x)=2x(d)g(x)=x

If intsinx(d)/(dx)("sec x")dx=f(x)-g(x)+C , then

If g(f(x))=|sinx|a n df(g(x))=(sinsqrt(x))^2 , then (a).f(x)=sin^2x ,g(x)=sqrt(x) (b).f(x)=sinx ,g(x)=|x| (c)f(x=x^2,g(x)=sinsqrt(x) (d).f\ a n d \g cannot be determined

inte^(-x)(1-tanx)secxdx is equal to a) e^(-x)secx+c b) e^(-x)tanx+c c) -e^(-x)tanx+c d) -e^(-x)secx+c

If (x-1) is a factor of polynomial f(x) but not of g(x) , then it must be a factor of (a) f(x)g(x) (b) -f\ (x)+\ g(x) (c) f(x)-g(x) (d) {f(x)+g(x)}g(x)

If inte^(secx) (secxtanxf(x)+secxtanx+tan^(2)x)dx=e^(secx)f(x)+c. Then f(x) is: (A) secx+xtamx+1/2 (B) xsecx+tanx+1/2 (C) xsecx+x^2tanx+1/2 (D) secx+tanx+1/2