In Fig. if AD = 4cm, BD = 3 cm and CB = 12 cm. then `cottheta=`

In the figure given below, AD = 4 cm, BD = 3 cm and CB = 12 cm, then cot theta equals:

In the given figure AD = 4 cm BD = 3 cm and CB = 12 cm . Find the value of cot theta

In the given figure. If AD = 12 cm, AE = 8 cm and EC = 14 cm, then what is the value (in cm) of BD?

In the given figure , if AD = 12 cm , AE = 8 cm and EC = 14 cm , then what is the value (in cm ) of BD ?

In the figure given below, AD=4cm,BD=3cm and CB=12 cm, then cotƟ equals

In Fig.5.48,AD=4cm,BD=3cm and CB=12cm, find cot theta*(12)/(5) (b) (5)/(12) (c) (13)/(12) (d) (12)/(13)( FIGURE)

In the figure, if DF||BC, AD = 3cm, BD = 4cm and BC = 14cm, then DE equals (a) 7cm (b) 6cm (c) 4cm (d) 3cm

In the figure, if DE || BC, AD = 3 cm, BD = 4 cm, and BC = 14 cm, then DE equals :

In a triangle ABC , DE is parallel to BC, AD = 3 cm, AE = 4cm and AC = 10 cm, then the value of BD in centimetres, is: triangle ABC में, DE, BC & समानांतर है, AD = 3 cm, AE= 4cm और AC = 10 cm, फिर BD (सेंटीमीटर में) मान है: