If the sum of the squares of the intercepts on the axes cut off by the tangent to the curve `x^(1//3)+y^(1//3)=a^(1//3) "with" (a>0)` at `(a//8,a//8)` is 2, then`a` has the value

If the sum of the squares of the intercepts on the axes cut off by the tangent to the curve x^(1//3)+y^(1//3)=a^(1//3)(a gt 0) at ((a)/(8),(a)/(8)) is 2 find the value of a.

If the sum of the squares of the intercepts on the axes cut off by tangent to the curve x^(1/3)+y^(1/3)=a^(1/3),\ a >0 at (a/8, a/8) is 2, then a= 1 (b) 2 (c) 4 (d) 8

The sum of squares of intercepts on the axes cut off by the tangents to the curve x^(2//3)+y^(2//3)=a^(2//3) (a gt 0) at ((a)/(8), (a)/(8)) is 2. Thus a has the value:

If the sum of the squares of the intercepts on the axes cut off by tangent to the curve x^((1)/(3))+y^((1)/(3))=a^((1)/(3)),a>0 at ((a)/(8),(a)/(8)) is 2, then a=1 (b) 2 (c) 4 (d) 8

The sum of the squares o the intercepts on the coordinates axes of any tangent to x^(2//3)+y^(2//3)=a^(2//3) is

If the sum of the squares of intercepts on axes made by a tangent at any point on the curve x^((2)/(3))+y^((2)/(3))=a^((2)/(3)) is a^(k) then k is:

Sum of the intercepts cut off by the line 2x + 3y = 6 on the axes is