Home
Class 12
PHYSICS
A magnetic needle is free to rotate in a...

A magnetic needle is free to rotate in a vertical plane which makes an angle of `60^@` with the magnetic meridian. If the needle stays in a direction making an angle of `tan^-1(2//sqrt3)` with the horizontal, what would be the true dip at that place?

Promotional Banner

Similar Questions

Explore conceptually related problems

A magnetic needle is free to rotate in a vertical plance which makes an angle of 60^@ with the magnetic meridian. If the needle stays in a direction making an angle of tan^(-1) (2sqrt(3)) with the horizontal, what would be the dip at that place?

A magnetic needle is free to rotate in a vertical plance which makes an angle of 60^@ with the magnetic meridian. If the needle stays in a direction making an angle of tan^(-1) (2sqrt(3)) with the horizontal, what would be the dip at that place?

A magnetic needle is free to rotate in a vertical plance which makes an angle of 60^@ with the magnetic meridian. If the needle stays in a direction making an angle of tan^(-1) (2sqrt(3)) with the horizontal, what would be the dip at that place?

At 52^@ from the magnetic meridian, a magnetic needle in a vertical plane makes an angle of 45^@ with the horizontal plane. Find the actual angle fo dip at that place.

A magnet makes an angle of 45^@ with the horizontal in a vertical plane making an angle of 30^@ with the magnetic meridian. Find the true value of the dip angle at that place.

The real angle of dip, if a magnet is suspended at an angle of 30^(@) to the magnetic meridian and the dip needle makes an angle of 45^(@) with horizontal, is: