If `s+3s` is 2 more than `t+3t`, then `s-t=`

The displacement of particle with respect to time is s = 3^(t3) - 7t^(2) + 5t + 8 where s is in m and t is in s, then acceleration of particle at t = ls is

What is the acceleration at the end of 3s of the particle that moves with the rule S = 3t^(2) + 5t + 2 ?

What is the acceleration at the end of 3 s of the particle that moves with the rule s=3t^2+5t+2 .

The displacement of a particle is represented by the equation, s=3 t^3 =7 t^2 +4 t+8 where (s) is in metres and (t) in seconds . The acceleration of the particle at t=1 s is.

If S=4 t^(3)-3t^(2)+2 , then acceleration is 42 "units" // sec ^(2) at the time t=

[" The acceleration ' "a" ' (in "m/s^(2)" ) of a particle is "],[" given by "a=3t^(2)+2t-2" ,where "t" is time in "],[" second.If the particle starts with "10m/s" at "t=],[0" ,then the velocity at "t=2s" is "]

The positon of an object moving along x-axis is given by x(t) = (4.2 t ^(2) + 2.6) m, then find the velocity of particle at t =0s and t =3s, then find the average velocity of particle at t =0 s to t =3s.