17.7 % of 286=?

7/8 of 90 % of 160=?

7/12 of 23% of 720 =?

105.01% "of 8451 - (3)/(7)% of 5006+9.999=?

Iron has a bcc unit cell with cell edge of 286.65 pm. The density of iron is 7.78 gcm^-3 . Use this information to calculate the Avogardo number (Fe=56.4)

The numbers a, b, c are the digits of a three digit number which satisfy 49a + 7b + c= 286.Then ,the value of 100a + 10b + c is

A hydrocarbon contains 7.7 % hydrogen. calculate the empirical formula.

If ''#'' means '"subtraction". "&" means "division", "@" means "addition" and "%" means "multiplication", then 217& 7# 3" @ "2%7=?

Find 7(1)/(2) % of Rs. 2400 .