A bomb of mass `4 m`, while moving on a parabolic path, explodes at highest point of its path. If breaks into two parts of mass ratio `1 : 3`, smaller part coming to rest. The range of this projectile was `60 m` in the absence of explosion. The distance of the second part from the point of projection when it strikes the ground is

A projectile of mass 3m explodes at highest point of its path. It breaks into three equalparts. One part retraces its path, the second one comes to rest. The range of the projectile was 100 m if no explosion would have taken place. The distance of the third part from the point of projection when it finally lands on the ground is -

A projectile of mass 3m explodes at highest point of its path. It breaks into three equalparts. One part retraces its path, the second one comes to rest. The range of the projectile was 100 m if no explosion would have taken place. The distance of the third part from the point of projection when it finally lands on the ground is -

In the previous problem , if a bomb explodes into three parts of mass ratio 1 : 1 : 2 , one smaller part retraces its path, the second smaller part coming to rest, the distance from the point of projection , where the heavier part strikes the ground is

A body is projected with a speed 160 m/s at an angle 53^(@) with the horizontal, At the highest point, body explodes into two pieces with mass ratio 1:3. Smaller piece comes to rest immediately after explosion. Find the distance of point from point of projection where heavier piece strikes the horizontal surface.

A particle of mass 4m is projected from the ground at some angle with horizontal. Its horizontal range is R . At the highest point of its path it breaks into two pieces of masses m and 3m , respectively, such that the smaller mass comes to rest. The larger mass finally falls at a distance x from the point of projection, where x is equal to

A particle of mass 4m is projected from the ground at some angle with horizontal. Its horizontal range is R . At the highest point of its path it breaks into two pieces of masses m and 3m , respectively, such that the smaller mass comes to rest. The larger mass finally falls at a distance x from the point of projection, where x is equal to

A particle of mass 3m is projected from the ground at some angle with horizontal. Its horizontal range is R. At the highest point of its path it breaks into two pieces of masses m and 2m respectively. The smallar mass comes to rest. The larger mass finally falls at a distance x from the point of projection where x is equal to (A) (4)/(3)R (B) (3)/(2)R (C) (5)/(4)R (D) 2.5R

A particle of mass 3m is projected from the ground at some angle with horizontal. Its horizontal range is R. At the highest point of its path it breaks into two pieces of masses m and 2m respectively. The smallar mass comes to rest. The larger mass finally falls at a distance x from the point of projection where x is equal to