Home
Class 12
MATHS
In triangle ABC, BC = 3, CA=5 and AB = 6...

In triangle ABC, BC = 3, CA=5 and AB = 6, then the value of `(1+sinA)/(sin\ A/2 + cos\ A/2)` is equal to

Promotional Banner

Similar Questions

Explore conceptually related problems

In triangle ABC , if AB=2,BC=4 and AC=5, then the value of (sinA-sinB)/(sinC) is equal to

In triangle ABC,/_B=90^(@),AC+BC=25 and AB=5, determine the value of sin A,cos A and tan A

If the median of triangle ABC through A is perpendicular AB, then the value of sinA cosB + 2sinB cosA is equal to

If the median of triangle ABC through A is perpendicular AB, then the value of sinA cosB + 2sinB cosA is equal to

In an isosceles triangle ABC. AB = BC = 10 cm and BC = 18 cm . Find the value of : sin ^(2) B + cos ^(2) C

In /_\ABC , right angled at B, AB=3 , BC=4 and CA=5 . Then value of sin^2A + cos^2A is:

If in a triangle ABC right angled at B, AB = 6 units and BC = 8 units, then find the value of sin A. cos C + cos A. sin C.

In /_\ABC , right angled at B, AB=3 , BC=4 and CA=5 . Then value of tan^2C+1 is:

In a triangle ABC, if AB=3, BC=4, CA=5. Then the surface area of the sphere having a radius equal to the inradius of the triangle is.